Ex 12.1, 3 (v) - Factorise z - 7 + 7 x y - x y z - Ex 12.1 (2024)

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Ex 12.1

Ex 12.1, 1 (i)

Ex 12.1, 1 (ii)

Ex 12.1, 1 (iii) Important

Ex 12.1, 1 (iv) Important

Ex 12.1, 1 (v)

Ex 12.1, 1 (vi) Important

Ex 12.1, 1 (vii)

Ex 12.1, 1 (viii) Important

Ex 12.1, 2 (i)

Ex 12.1, 2 (ii) Important

Ex 12.1, 2 (iii)

Ex 12.1, 2 (iv) Important

Ex 12.1, 2 (v)

Ex 12.1, 2 (vi)

Ex 12.1, 2 (vii)

Ex 12.1, 2 (viii) Important

Ex 12.1, 2 (ix)

Ex 12.1, 2 (x) Important

Ex 12.1, 3 (i)

Ex 12.1, 3 (ii) Important

Ex 12.1, 3 (iii)

Ex 12.1, 3 (iv) Important

Ex 12.1, 3 (v) Important You are here

Ex 12.2→

Chapter 12 Class 8 Factorisation

Serial order wise

  • Ex 12.1

  • Ex 12.2
  • Ex 12.3
  • Examples
  • Identify and correct errors in the sentences

Last updated at April 16, 2024 by Teachoo

Ex 12.1, 3 (v) - Factorise z - 7 + 7 x y - x y z - Ex 12.1 (2)

Transcript

Ex 12.1, 3 Factorise. (v) z – 7 + 7 x y – x y zz – 7 + 7 x y – x y z= (z − 7) + (7xy − xyz)= (z − 7) + 𝒙y (7 − z)= (z −7) + 𝑥y × −(z − 7)= (z − 7) − 𝑥y (z − 7)Taking (z − 7) common= (z − 7) (1 − 𝒙y)

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Ex 12.1, 3 (v) - Factorise z - 7 + 7 x y - x y z - Ex 12.1 (3)

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

Ex 12.1, 3 (v) - Factorise z - 7 + 7 x y - x y z - Ex 12.1 (2024)

FAQs

How to factorise z 7 7 xy xyz? ›

=(z−7)(1−xy)

What is the factorization of a2 8a 16? ›

a2+8a+16=(a)2+2×a×4+(4)2=(a+4)2 [∵ (x+y)2=x2+2xy+y2]

How do I Factorise this equation? ›

Factorising
  1. To factorise an expression fully, take out the highest common factor (HCF) of all the terms. ...
  2. Factorise 6 x + 9 .
  3. To factorise this expression, look for the HCF of and 9 which is 3. ...
  4. The HCF of 6 x + 9 is 3. ...
  5. 6 x ÷ 3 = 2 x and.
  6. This gives:
  7. 3 ( 2 x + 3 ) = 3 × 2 x + 3 × = 6 x + 9.

What is the formula for factorize? ›

The general factorization formula is expressed as N = Xa × Yb × Zc. Here, a, b, c represent the exponential powers of the factors of a factorized number.

What is the factorization of 12a 2 b 15ab2? ›

12a2b+15ab2 = 3ab (4a+5b)

How do you solve factorization? ›

To solve an quadratic equation using factoring :
  1. Transform the equation using standard form in which one side is zero.
  2. Factor the non-zero side.
  3. Set each factor to zero (Remember: a product of factors is zero if and only if one or more of the factors is zero).
  4. Solve each resulting equation.

What is the quadratic equation having its roots as a factor of 7? ›

Expert-Verified Answer

∴ the roots of the given quadratic equation are 7/2 and 1 both of which are factors of 7. Therefore, the quadratic equation that has its roots as factors of 7 is x² - 8x +7=0.

How to factorise ax, bx, ay by? ›

To Find, The factorized form of this expression. So, after factorizing, the expression becomes (x-y)(a+b). Hence, the factorized form of ax+bx-ay-by is (x-y)(a+b).

How to factorise 15xy 6x 5y 2? ›

Detailed Solution
  1. ⇒ 15xy - 6x + 5y - 2.
  2. Concept used:
  3. ⇒ 15xy - 6x + 5y - 2.
  4. ⇒ 3x (5y - 2) +1 (5y - 2)
  5. ⇒ (5y - 2) (3x + 1)
Apr 8, 2024

When we factorise x2 + 5x + 6 then we get? ›

Thus, the algebraic x2 + 5x + 6 has elements = (x+3)(x+2).

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